How do you solve for x for this equation: 2sin(2x-60°)=1?

where -2π ≤ x ≤ 2π

[π=pi]

I am unsure of where to start for this one (Shake)

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- Apr 7th 2009, 09:43 PMJd09How do you solve for x when 2sin(2x-60°)=1?
How do you solve for x for this equation: 2sin(2x-60°)=1?

where -2π ≤ x ≤ 2π

[π=pi]

I am unsure of where to start for this one (Shake) - Apr 7th 2009, 09:48 PMJhevon
- Apr 7th 2009, 10:21 PMJd09
Is this correct?

(sin-1)sin(2x-60)=1/2(sin-1)

(2x-60)=30

x=45

?? - Apr 7th 2009, 10:38 PMJhevon
- Apr 7th 2009, 10:48 PMJd09
135...

and would -135 work as well? - Apr 7th 2009, 10:53 PMJd09How do you solve for x when 2sin(2x-60°)=1?
Thank you for your help!