I can't seem to figure the rest of this out:
Solve for All possible values of x: 4sin^2(x)-1=0?
So far I have:
Let m = sinx
So: 4m^2-1=0
How would I go about solving the rest?
Actually I don't really see the need for the substitution.
$\displaystyle 4sin^2x-1=0$
$\displaystyle sin^2x=1/4$
$\displaystyle sinx=1/2, -1/2$
The critical angle is pi/6. Thus if you are looking for angles between 0 and 2*pi, the possible angles are pi/6, 5*pi/6, 7*pi/6, 11*pi/6.
Hope this helps.