So I am taking this Trig class and it is kicking my little bunns. I need help with my homework and I managed to get a little help earlier today but I'm still lost. Can anyone help me please? Thank you to anyone who helps me with this.

1. Find the length of the arc (to the nearest tenth of a unit) intercepted by each angle with r = 9cm: 240 degrees
a. ≈37.7 cm
b. ≈21.60 cm
c. ≈12.36 cm
d. ≈515.66 cm

2. For questions 2-5 Use the given sides and or measures of angles of a right triangle to find the requested side and/or angle. In each case y=90 degrees. alpha = 23.4 degrees: find B.
a. 156.6 degrees
b. 66.6 degrees
c. 6.6 degrees
d. 180 degrees

3. If a = 6.3 and b = 47 degrees: find b
a. ≈ 4.61
b. ≈ 4.30
c. ≈ 6.76
d. 5.59

4. a = 5.31 and c = 7.27: find alpha
a. ≈ 0.73 degrees
b. ≈ 0.01 degrees
c. ≈ 46.92 degress
d. ≈ 43.08 degrees

5. a = 6.2 and b = 9.3: find c
a. ≈ 7.55
b. ≈ 56.93
c. ≈ 3.24
d. ≈ 2.75
e. ≈ 3.29

6. Solve for the triangle alpha using law of cosines with 3 sides given as a = 3.4, b = 2.7 and c = 1.3
a. ≈ 111.6 degrees
b. ≈ 68.4 degrees
c. ≈ 47.6 degrees
d. ≈ 20.8 degrees

7. Solve for the triangle beta using law of cosines with the 3 sides given as a = 3.4, b = 2.7 and c = 1.3
a. ≈ 111.6 degrees
b. ≈ 68.4 degrees
c. ≈ 47.6 degrees
d. ≈ 20.8 degrees

2. 7 questions --hmm sorry to disappoint you will have to show your try and where you got stuck for EACH and every one

By the way do these questions count on your grading/marks in an exam?

3. Originally Posted by Samantha247

1. Find the length of the arc (to the nearest tenth of a unit) intercepted by each angle with r = 9cm: 240 degrees
a. ≈37.7 cm
b. ≈21.60 cm
c. ≈12.36 cm
d. ≈515.66 cm

You should know the formula for the circumference of a circle:
C = 2 * pi * r
& you should know that there are 360 degrees in a circle.
Since the arc is 240 degrees, the arc length will be proportional
to the circumference.

4. Adarsh- These questions are part of a homework assignment as I stated in the beginning of the post. I am not good at math at all, but I have to take this class. I have no way around it. Can you please re-phrase your statement.... what do I have to show?

5. for 3,4,5:

3: Tan = opposite/adjacent so Tan(47) = B/6.3, solve for B
4: Sin= Opposite/hypotenuse so Sin(alpha) = 5.31/7.27, solve for alpha using inverse sin
5. Use pythagoreans theorem - c=square root of (6.2)^2 + (9.3)^2

6/7: use law of cosine: C^2 = A^2 +B^2 - 2ABCos(gamma)