Can someone PLEASEEEEEE help me prove this trig identity.

I did it down to where I have

LS:

sinx/cosx

RS:

-sinx

I am not sure where I went wrong,

can someone please help

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- April 6th 2009, 07:57 AMskeske1234(cos^2x-sin^2x)/cos^2x+sinxcosx=1-tanx
Can someone PLEASEEEEEE help me prove this trig identity.

I did it down to where I have

LS:

sinx/cosx

RS:

-sinx

I am not sure where I went wrong,

can someone please help - April 6th 2009, 08:06 AMADARSH
LHS:

For numerator use formula

a^2 - b^2 = (a-b)(a+b)

So

cos^2(x) - sin^2 (x) = (cos(x) - sin(x))**(cos(x) + sin(x))**

Denominator

cos^2(x) +cos(x)sin(x) = cos(x)**(cos(x) +sin(x))**

Divide numerator by denominator

The things in bold get cancelled

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One more thing try to avoid writing like thissssssss (Smile)

Adarsh (Happy) - April 6th 2009, 08:09 AMstapel
Until you show your steps, I'm afraid

*we*can't be sure where you went wrong, either. Sorry! (Blush)

Please reply with a clear listing of your work and reasoning so far. Thank you! :D - April 6th 2009, 08:30 AMADARSH
(Wait) Sorry to disappoint you SHOULD start a new thread for a new problem

Take Care of Yourself & Rules

Adarsh - April 6th 2009, 09:19 AMthepd