Find all solutions to the equation in the interval [0, 2pi)

Problem: sin 2x = -sin x

My attempt:

I'm thinking of making it equal to 0

sin2x - sin x = 0

factor out sin

sin(2x-1) = 0

2x-1= 0

x =1/2

I dont know if i'm going the right direction .

sin(1/2) ?

on unit circle sin 1/2 = pi/6, 5pi/6, 11pi/6