Find all solutions to the equation in the interval [0, 2pi)
Problem: sin 2x = -sin x
My attempt:
I'm thinking of making it equal to 0
sin2x - sin x = 0
factor out sin
sin(2x-1) = 0
2x-1= 0
x =1/2
I dont know if i'm going the right direction .
sin(1/2) ?
on unit circle sin 1/2 = pi/6, 5pi/6, 11pi/6