I have no idea how to solve an equation -1.2sin2t+0.8cost=0.8 (tried all trig formulas and substitution method) If anybody could help? Thanks.
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Originally Posted by Romanka I have no idea how to solve an equation -1.2sin2t+0.8cost=0.8 (tried all trig formulas and substitution method) Is the first term -1.2 sin(2t) or -1.2 sin^2(t)? Thank you!
-1.2sin(2t)+0.8cost=0.8
Originally Posted by Romanka -1.2sin(2t)+0.8cost=0.8 sin(2t) = 2sin(t)cos(t) Multiply that by -1.2 and factor out cos(t). Then solve using both cos and sin
I tried all these steps, but there is 0.8 in the right side. I have 3sintcost-cost+1=0 and can't solve it
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