I know that how to work with cos, sin and tan...
tanˆ2x + tanx = 0
tanx(tanx + 1) = 0
were you given an interval to find solutions for x ?
tanx = 0
x = undefined
no, that's not correct
tanx + 1 = 0
tanx = -1
x = -45
that is one solution, x = what other values?
But, how do I solve:
(√3)csc(x) - 2 = 0
solutions for the last equation are straight off the unit circle, which you have memorized, right ?