Originally Posted by

**Ian1779** Hi

I am finding this question tough (attached), I think I may have stumbled on the answer but could do with some confirmation I'm on the right path.

Right, so far I have found the length $\displaystyle BC = \sqrt 82$ using Phythagoras.

Now I need to determine $\displaystyle sin \theta$,$\displaystyle cos \theta$ and $\displaystyle tan \theta$

This is where I am stuck. It is not a right angled triangle so can I use SOHCAHTOA?

Never the less I have attempted this way and got

$\displaystyle tan \theta = 1/9$

$\displaystyle sin \theta = 1/\sqrt82$

$\displaystyle cos \theta = 9/\sqrt82$

Which all give the same answer incidentally - is this the right approach or am I off in the completely wrong direction?

I get the last part about the two line notation, but am not sure what values to use for x and y.

Please help.

Thanks