# How do I solve "sin x = .948"?

• Mar 29th 2009, 02:18 PM
iggy1110
How do I solve "sin x = .948"?
I know that it involves an arc(trig function) but I don't exactly know which. I'm having a (very) rough year in trigonometry but was hoping someone could teach me how to solve that basic problem.
• Mar 29th 2009, 02:18 PM
stapel
Quote:

Originally Posted by iggy1110
I know that it involves an arc(trig function) but I don't exactly know which.

To undo a sine, try using the arc-sine. (Wink)
• Mar 29th 2009, 02:20 PM
iggy1110
Quote:

Originally Posted by stapel
To undo a sine, try using the arc-sine. (Wink)

Thank you very much =)

So would the equation I use to solve look like this:

x = arcsin .9486
• Mar 29th 2009, 02:36 PM
e^(i*pi)
Quote:

Originally Posted by iggy1110
Thank you very much =)

So would the equation I use to solve look like this:

x = arcsin .9486

Yep, since sin(x) repeats itself the answer would be $\displaystyle x = arcsin(.9486) \pm 2k\pi$ where k is an integer and radians are used