Originally Posted by
skeske1234 I have up to:
[2sin(2x-x)]/sin2x
[2sin(2x-x)]/2sinxcosx
Questions:
how do I cancel 2sin(2x-x) so that it equals 1/cosx?
does 2sin(2x-x) really equal 2sin(x) or any number for x?
so can I cancel out the 2sin(2x-x)/2sinx?