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Math Help - Trigonomteric Ratios and Special Angles

  1. #1
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    Trigonomteric Ratios and Special Angles

    Can someone please explain to me how to solve this question:

    Determine an exact value for each expression:

    a) [cot(pi/4)]/[(cos(pi/3))(csc(pi/2))]

    b) [cos(pi/6)][csc(pi/3)]+sin(pi/4)

    even if you explain one of them, that would be appreciated! I don't understand this question at all, so please be detailed.

    thank you so much
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  2. #2
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    Quote Originally Posted by skeske1234 View Post
    Can someone please explain to me how to solve this question:

    Determine an exact value for each expression:

    a) [cot(pi/4)]/[(cos(pi/3))(csc(pi/2))]

    b) [cos(pi/6)][csc(pi/3)]+sin(pi/4)

    even if you explain one of them, that would be appreciated! I don't understand this question at all, so please be detailed.

    thank you so much
    you're expected to know these values from your knowledge of basic identities and values of trig ratios on the unit circle ...

    \cot\left(\frac{\pi}{4}\right) = \frac{\cos\left(\frac{\pi}{4}\right)}{\sin\left(\f  rac{\pi}{4}\right)} = 1

    \cos\left(\frac{\pi}{3}\right) = \frac{1}{2}

    \csc\left(\frac{\pi}{2}\right) = \frac{1}{\sin\left(\frac{\pi}{2}\right)} = 1

    \cos\left(\frac{\pi}{6}\right) = \frac{\sqrt{3}}{2}

    \csc\left(\frac{\pi}{3}\right) = \frac{1}{\sin\left(\frac{\pi}{3}\right)} = \frac{2}{\sqrt{3}}

    \sin\left(\frac{\pi}{4}\right) = \frac{\sqrt{2}}{2}

    use these values to evaluate each expression.


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