Find the solution of the equation if $\displaystyle 0 \leq x \leq 2\pi $ Question $\displaystyle 4sin^2t-1=0$ Attempt: t=-30/330 t=30/150 Is my attempt correct? Thank you
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Hi $\displaystyle 4 \sin^2t - 1 = 0$ can be factored in $\displaystyle (2 \sin t - 1)(2 \sin t + 1) = 0$ which implies $\displaystyle \sin t = \frac12$ or $\displaystyle \sin t = -\frac12$
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