Hello, uhhuh!

Did you try to make a sketch?

A wire is stretched from the top of a 200 ft building to a point on the ground

130 ft from the building. What angle does the wire make with the ground? Code:

A *
|\
| \
| \
| \
200 | \
| \
| \
| \
| θ \
B * - - - - * C
130

$\displaystyle AB$ is the building: .$\displaystyle AB = 200$

The wire is stretched from $\displaystyle A$ to $\displaystyle C$: .$\displaystyle BC = 130$

We want: .$\displaystyle \theta \,=\,\angle ACB$

In right triangle $\displaystyle ABC\!:\;\;\tan\theta \:=\:\frac{200}{130}$

Therefore: .$\displaystyle \theta \;=\;\arctan\left(\tfrac{200}{130}\right) \:=\: 57.97613244 \;\approx\;58^o$