Results 1 to 3 of 3

Math Help - trignometric solution

  1. #1
    Newbie
    Joined
    Mar 2009
    Posts
    5

    trignometric solution

    cos(sqrt(x))=0

    i got that x = (2n+1)*pi/2 where n = integers from 1 to infinity.

    is this correct?
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor
    skeeter's Avatar
    Joined
    Jun 2008
    From
    North Texas
    Posts
    11,698
    Thanks
    454
    Quote Originally Posted by gsds View Post
    cos(sqrt(x))=0

    i got that x = (2n+1)*pi/2 where n = integers from 1 to infinity.

    is this correct?
    \sqrt{x} = (2n+1)\left(\frac{\pi}{2}\right) , n \in \mathbb{Z}

    square both sides.
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Member
    Joined
    Jan 2009
    Posts
    108
    Quote Originally Posted by gsds View Post
    cos(sqrt(x))=0

    i got that x = (2n+1)*pi/2 where n = integers from 1 to infinity.

    is this correct?
    cos(sqrt(x))=0

    sqrt(x)= (2n+1)*pi/2

    x = [(2n+1)*pi/2]^2

    (might want to distribute this out)
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Trignometric Question
    Posted in the Trigonometry Forum
    Replies: 4
    Last Post: August 26th 2010, 12:54 AM
  2. Trignometric Integrals
    Posted in the Calculus Forum
    Replies: 2
    Last Post: February 6th 2010, 05:11 PM
  3. trignometric differentiation
    Posted in the Calculus Forum
    Replies: 1
    Last Post: November 17th 2009, 05:29 PM
  4. trignometric simplify
    Posted in the Trigonometry Forum
    Replies: 4
    Last Post: May 6th 2008, 01:31 PM
  5. Trignometric Functions
    Posted in the Trigonometry Forum
    Replies: 1
    Last Post: May 13th 2007, 06:31 PM

Search Tags


/mathhelpforum @mathhelpforum