Solve in the interval [0,2], answer as a multiple of pi.
The first on is (sin(t))^2=1/2 and her is what I did.
t= sqrt(1/2)= +-sqrt(2)/2
so, t=pi/4 or t=5pi/4
the next one is the same type but uses cosine.
so, t=pi/6 or -5pi/6
When someone has time could they look this over and let me know if I am going in the right direction with these.
Thank you very much!!