Solve in the interval [0,2], answer as a multiple of pi.

The first on is (sin(t))^2=1/2 and her is what I did.

t= sqrt(1/2)= +-sqrt(2)/2

so, t=pi/4 or t=5pi/4

the next one is the same type but uses cosine.

(cos(t))^2=3/4

t= +-sqrt(3)/2

so, t=pi/6 or -5pi/6

When someone has time could they look this over and let me know if I am going in the right direction with these.

Thank you very much!!

Keith Stevens