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Thread: identity help

  1. March 25th 2009, 05:15 AM #1
    TYTY
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    identity help

    <br /> <br /> \frac{\sec{x}\tan{x}}{\tan^3{x}} = \frac{\cos{x}}{\sin{x}}<br /> <br />

    the part in the middle is what I am missing
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  2. March 25th 2009, 06:18 AM #2
    Soroban
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    Hello, TYTY!

    \frac{\sec x\tan x}{\tan^3\!x} \:=\: \frac{\cos x}{\sin x}

    the part in the middle is what I am missing .     . . . oh, is that all?

    Please check the problem again . . .

    The given statement is not an identity.
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  3. March 25th 2009, 06:58 AM #3
    masters
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    Quote Originally Posted by TYTY View Post
    <br /> <br /> \frac{\sec{x}\tan{x}}{\tan^3{x}} = \frac{\cos{x}}{\sin{x}}<br /> <br />

    the part in the middle is what I am missing
    Hi TYTY,

    Maybe, you meant

    \frac{\sec{x}\tan{x}}{\tan^3{x}} = \frac{\cos{x}}{\sin^2{x}}
    Last edited by masters; March 25th 2009 at 07:59 AM.
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  4. March 25th 2009, 07:05 AM #4
    TYTY
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    ouch

    better start that whole problem over again...
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