# Math Help - identity help

1. ## identity help

$

\frac{\sec{x}\tan{x}}{\tan^3{x}} = \frac{\cos{x}}{\sin{x}}

$

the part in the middle is what I am missing

2. Hello, TYTY!

$\frac{\sec x\tan x}{\tan^3\!x} \:=\: \frac{\cos x}{\sin x}$

the part in the middle is what I am missing .
. . . oh, is that all?

Please check the problem again . . .

The given statement is not an identity.

3. Originally Posted by TYTY
$

\frac{\sec{x}\tan{x}}{\tan^3{x}} = \frac{\cos{x}}{\sin{x}}

$

the part in the middle is what I am missing
Hi TYTY,

Maybe, you meant

$\frac{\sec{x}\tan{x}}{\tan^3{x}} = \frac{\cos{x}}{\sin^2{x}}$

4. ouch

better start that whole problem over again...