# Thread: Trig; Sin Problem:

1. ## Trig; Sin Problem:

Evaluate:

$\displaystyle sin^-1\frac{1}{2}^2$

2. Originally Posted by qbkr21
Evaluate:

$\displaystyle sin^-1\frac{1}{2}^2$
Well, the arcsine of 1/2 is $\displaystyle \pi/6$
So the answer is the square of that,
$\displaystyle (\pi/6)^2=\pi^2/12$

3. Originally Posted by ThePerfectHacker
Well, the arcsine of 1/2 is $\displaystyle \pi/6$
So the answer is the square of that,
$\displaystyle (\pi/6)^2=\pi^2/12$
He really wrote $\displaystyle (\pi/6)^2=\pi^2/36$ but the evil computer trolls changed it on him.

-Dan