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Math Help - Solving Trigonometric equations 2

  1. #1
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    Solving Trigonometric equations 2

    Question
    tan^3x-tanx=0 if  0 \leq x \leq \frac{\pi}{2}

    Attempt

     tan(tan+1)(t-1)=0


    Thank you
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  2. #2
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    Quote Originally Posted by mj.alawami View Post
    Question
    tan^3x-tanx=0 if  0 \leq x \leq \frac{\pi}{2}

    Attempt

     tan(tan+1)(t-1)=0


    Thank you
    Hi

    That's OK
    \tan x (\tan x+1)(\tan x-1)=0

    \tan x = 0 \rightarrow x=0
    \tan x = 1 \rightarrow x=\frac{\pi}{4}
    \tan x = -1 \rightarrow no solution in \left[0,\frac{\pi}{2}\right]
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  3. #3
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    Quote Originally Posted by mj.alawami View Post
    Question
    tan^3x-tanx=0 if  0 \leq x \leq \frac{\pi}{2}

    Attempt

     tan(tan+1)(t-1)=0


    Thank you
    1.Factor out tan(x) to get tan(x)=0

    Now solve the quadratic for the other solutions remembering there is an asymptote at \frac{\pi}{2}
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