Solving Trigonometric equations 2

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March 23rd 2009, 11:03 AM
mj.alawami

Solving Trigonometric equations 2

Question
$tan^3x-tanx=0$ if $0 \leq x \leq \frac{\pi}{2}$

Attempt

$tan(tan+1)(t-1)=0$ (Crying)

Thank you
March 23rd 2009, 11:19 AM
running-gag

Quote:

Originally Posted by mj.alawami

Question
$tan^3x-tanx=0$ if $0 \leq x \leq \frac{\pi}{2}$

Attempt

$tan(tan+1)(t-1)=0$ (Crying)

Thank you

Hi

That's OK
$\tan x (\tan x+1)(\tan x-1)=0$

$\tan x = 0 \rightarrow x=0$
$\tan x = 1 \rightarrow x=\frac{\pi}{4}$
$\tan x = -1 \rightarrow$ no solution in $\left[0,\frac{\pi}{2}\right]$
March 23rd 2009, 11:20 AM
e^(i*pi)

Quote:

Originally Posted by mj.alawami

Question
$tan^3x-tanx=0$ if $0 \leq x \leq \frac{\pi}{2}$

Attempt

$tan(tan+1)(t-1)=0$ (Crying)

Thank you

1.Factor out tan(x) to get $tan(x)=0$

Now solve the quadratic for the other solutions remembering there is an asymptote at $\frac{\pi}{2}$

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