In the triangle ABC, a= 10, b= 12 and B= 58°. Find A, C and c.
Here is what I've done so far:
b/sin B = a/sin A
12/sin 58° = 10/sin A
sin 58°/12 = sin A/10
sin A = (10 * sin 58°)/12
A = inverse sin (10 * sin 58°/12)
= 44 degrees and 58 minutes
What do I do next? How can I find C and c? If anyone could show me the complete working out to the rest of the problem that would be appreciated! And please keep the working out simple...I'm new at this!