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Math Help - Inverse Function with multiple x terms.

  1. #1
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    Inverse Function with multiple x terms.

    Hi I'm trying to find the inverse function of f(x) = 8+x^2+tan{\frac{\pi*x}{2}} where -1< x <1 and f^{-1}(8)
    The main place i am having trouble is I don't know how to rearrange for x when there is more than 1 x term. The best I've done is; by letting f(x)= y, get the equation y-8=x^2+tan{\frac{\pi*x}{2}}which doesn't seem to be a great deal better.

    Any ideas would be greatly appreciated.
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by mattty View Post
    Hi I'm trying to find the inverse function of f(x) = 8+x^2+tan{\frac{\pi*x}{2}} where -1< x <1 and f^{-1}(8)
    The main place i am having trouble is I don't know how to rearrange for x when there is more than 1 x term. The best I've done is; by letting f(x)= y, get the equation y-8=x^2+tan{\frac{\pi*x}{2}}which doesn't seem to be a great deal better.

    Any ideas would be greatly appreciated.
    please state the problem in its entirety. i suspect that what you were asked to find is something along the lines of \frac d{dx}f^{-1}(8), in which case, finding the inverse function is not necessary. if all you are after is f^{-1}(8), finding the inverse function is still not necessary
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  3. #3
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    If , where , find .
    That is the question verbatim. If finding the inverse function is not necessary then would you mind giving any hints as to the path i should be taking then? It wouldn't be as simple as letting f(x)=8 would it? and then since we know that x is between -1 and 1 sub 0 in and f^{-1}=0

    If it's that simple I will quite happily kick myself
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  4. #4
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by mattty View Post
    If , where , find .
    That is the question verbatim. If finding the inverse function is not necessary then would you mind giving any hints as to the path i should be taking then? It wouldn't be as simple as letting f(x)=8 would it? and then since we know that x is between -1 and 1 sub 0 in and f^{-1}{\color{red}(8)}=0

    If it's that simple I will quite happily kick myself
    start kicking
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  5. #5
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    le sigh, thanks a bunch
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