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Math Help - trig equation

  1. #1
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    trig equation

    Hi!
    I know this is a fairly simple trig equation but i just keep getting it wrong!

    equation:
    tan(40-2x)=3^1/2 (root 3)

    Can someone please help me?

    Thank u!!! =)
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  2. #2
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    Quote Originally Posted by Nancy View Post
    Hi!
    I know this is a fairly simple trig equation but i just keep getting it wrong!

    equation:
    tan(40-2x)=3^1/2 (root 3)
    You should provide your work so that we can point out any mistakes.

    Begin by noting that \sqrt3=\frac{2\sqrt3}2=\frac{\sqrt3/2}{1/2}. The tangent is sine divided by cosine, so for what angles does sine equal \frac{\sqrt3}2 and cosine equal \frac12?
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  3. #3
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    you need to calculate when the argument of the tan is
    equal to \sqrt{3}
    Remembering that \tan{x} = \sqrt{3} when
    x=\frac{\pi}{3}+k\pi as also Reckoner said.

    Then u can write:

    40-2x= \frac{\pi}{3}+k\pi

    2x=-\frac{\pi}{3}-k\pi+40

    x=-\frac{\pi}{6}-k\frac{\pi}{2}+20

    simplifying:

    x=\frac{120-\pi}{6}-k\frac{\pi}{2}
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  4. #4
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    Smile

    Thank u! for ur help....i figured it out....
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