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**silverbird** Hi my maths text book has a question that says:

Solve $\displaystyle sin^2\theta$ for $\displaystyle -180\leq \theta \leq180$

and the example shows these first few lines of working:

$\displaystyle sin^2\theta=\frac{1}{2}$

$\displaystyle sin\theta = \pm\sqrt{\frac{1}{2}}$

$\displaystyle sin\theta =\pm\frac{1}{\sqrt{2}}$

but what iam wandering is what about the theta (angle) if you square root one side wouldn't you need to square root the theta as well not just the $\displaystyle sin^2$

and wouldn't the second line look like this

$\displaystyle sin\sqrt{\theta}=\pm\sqrt{\frac{1}{2}}$

thanx for your help in advance