Greetings.
Given: I have a right triangle with sides of 5cm, 13cm, and sqrt(194)cm.
What is the equation to calculate the side of 5cm in radians? I'm pretty sure it involves atan, but am unsure how to implement it.
Thanks.
Greetings.
Given: I have a right triangle with sides of 5cm, 13cm, and sqrt(194)cm.
What is the equation to calculate the side of 5cm in radians? I'm pretty sure it involves atan, but am unsure how to implement it.
Thanks.
As Las said, angles are measured in radians, not the length of a side. It is true that $\displaystyle 5^2+ 13^2= 194$ so this is a right triangle. You can use any of the trig functions to answer this. Letting $\displaystyle \theta$ be the angle opposite the leg of length 5, we have
(1)$\displaystyle tan(\theta)= \frac{5}{13}$
(2)$\displaystyle cot(\theta)= \frac{13}{5}$
(3)$\displaystyle sin(\theta)= \frac{5}{\sqrt{94}}$
(4)$\displaystyle cos(\theta)= \frac{13}{\sqrt{94}}$
(5)$\displaystyle sec(\theta)= \frac{\sqrt{94}}{13}$
(6)$\displaystyle csc(\theta)= \frac{\sqrt{94}}{5}$
Use any one of those.