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Math Help - Solution of the sec equation

  1. #1
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    Solution of the sec equation

    Question:
    Find the solution of the equation if it is in the first quadrant

     sec^2x-1=0

    Attempt:
     secx=1 ; x= \frac {1}{arccos 1}
    I keep getting infiniate as my answer


    Thank you
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  2. #2
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    Quote Originally Posted by mj.alawami View Post
    Question:
    Find the solution of the equation if it is in the first quadrant

     sec^2x-1=0

    Attempt:
     secx=1 ; x= \frac {1}{arccos 1}
    I keep getting infiniate as my answer


    Thank you
    \sec^2{x} = 1

    \frac{1}{\cos^2{x}} = 1

    1 = \cos^2{x}

    \pm 1 = \cos{x}

    If \cos{x} = -1 then x = \{\dots -3\pi, -\pi, \pi, 3\pi, \dots\} and if \cos{x} = 1 then x = \{ \dots, -2\pi, 0, 2\pi, \dots \}.


    Therefore x = n\pi where n is an integer.
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