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**lightningstab714** Find $\displaystyle \sin \left( {\theta} \right)$, $\displaystyle \cos \left( {\theta} \right)$, and $\displaystyle \tan \left( {\theta} \right)$ given that $\displaystyle \cot \left( {2\theta} \right) = -5/12$; 2*θ* is in Quadrant II.

I'm pretty sure solving this involves the double-angle (or maybe a half-angle) identity for tangent (the inverse of cotangent), but I'm not sure how to get $\displaystyle \cot \left( {2\theta} \right) = -5/12$ in terms of tangent. Please just help me get this started. I can solve for $\displaystyle \sin \left( {\theta} \right)$ and $\displaystyle \cos \left( {\theta} \right)$ if it were written in terms in terms of tangent. Thanks.