Hello, Keith!

Your arithmetic is a bit off . . .

Given: in Q2. . Find

Using your approach, I'd do it like this . . .

. .

Then: .

Since is in Q2, cosine is negative: .

Therefore: .

~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~

I prefer to do it like this . . .

We're given: .

Since , I can make a sketch.Code:* | : \ | 3 : \4 | : \ θ -+-------*-------- |

We have: .

Using Pythagorus, we find that:

. . And now we can writeanyof the trig functions.