I can simplify it all the way down to cos(6x) + sin(3x) = 0, however I get stuck here :(Code:`Find all solutions of`

2 cos(3x)^2 + sin(3x)

Printable View

- Nov 21st 2006, 08:28 PMCcrowPlease help me (solve trigonometry equation)Code:
`Find all solutions of`

2 cos(3x)^2 + sin(3x)

- Nov 22nd 2006, 03:28 AMtopsquark
- Nov 22nd 2006, 06:45 AMSoroban
Hello, Ccrow!

I'll take a*guess*at what you meant . . .

Quote:

Find all solutions of: .

Replace with

. . then: .

And we have the quadratic: .

Quadratic Formula: .

We must discard the positive square root: .

So we have: .

Therefore: .

- Nov 26th 2006, 03:41 PMputnam120
Soroban you can have but you will be required to use complex numbers. I assume that he only wanted the real solutions any way, but just thought id point that out.