Hello, Tweety!

A helicopter flies on a bearing of 200° from $\displaystyle A$ to $\displaystyle B$, where $\displaystyle AB = 70$ km.

It then flies on a bearing of 150° from $\displaystyle B$ to $\displaystyle C$, where $\displaystyle C$ is due south of $\displaystyle A$.

Find the distance from $\displaystyle C$ to $\displaystyle A.$ The first leg of the flight looks like this: Code:

:
:
:
A *
/ 200°
70 /
/
/
/
B *

The second leg looks like this: Code:

:
:
B * 150°
:\
: \
: \
\
\
* C

So the diagram should look like this: Code:

: * A
: * |
: 70 *20°|
: * |
:20°* |
: * |
B * 130° |
: * |
:30°* |
: * |
: *30°|
: * |
: * C