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Given: .

Find: .

We are told that: .

Since , we know that: .

Pythagorus says: .

. . so we have: .

Since is in quadrant 3,

So we have: .

Now with a few identities, we can tackle the questions . . .

. . .Since is in quadrant 3, is in quadrant 2 where cosine is negative.

. . .Therefore: .

. . .Since is in quadrant 3, is in quadrant 2 where sine is positive.

. . .Therefore: .