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Thread: Sin

  1. August 22nd 2005, 08:26 AM #1
    kdstalnaker
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    Sin

    Find sinB given that 0<B<(pie/2) and cosB=(1/5)
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  2. August 22nd 2005, 11:24 AM #2
    rgep
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    In a right-angled triangle sin = opposite/hypotenuse, cos = adjacent/hypotenuse. So if cos = 1/5, then consider a triangle with hypotenuse 5 and a side of 1. The other = ... by Pythagoras and so sin = ... / ???
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