Find sinB given that 0<B<(pie/2) and cosB=(1/5)

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- August 22nd 2005, 08:26 AMkdstalnakerSin
Find sinB given that 0<B<(pie/2) and cosB=(1/5)

- August 22nd 2005, 11:24 AMrgep
In a right-angled triangle sin = opposite/hypotenuse, cos = adjacent/hypotenuse. So if cos = 1/5, then consider a triangle with hypotenuse 5 and a side of 1. The other = ... by Pythagoras and so sin = ... / ???