Originally Posted by

**mattty** Hi, I've been going around in circles with this question, coming back to the original equation over and over because I can't honestly figure out what I'm supposed to be doing.

The question is:

Find all the values of x in the interval $\displaystyle [0,2\pi]$ such that $\displaystyle 2sin^2x=1$

I realize that I am meant to be looking for values between 0 and $\displaystyle 2\pi$ but I've no idea how to manipulate the trig identities in order to do that.

Any help would be appreciated.