Hii I reallyy need to solve this question. could you guys help me and also solve it? thankss
Two buildings of equal height are 40m apart and at a point on the horizontal line joining their feet the angles of elevation of the top of the building are 47 degrees and 28 degrees.
Show that the height (h) of the building is given by:
h = 40tan47*tan28*
Show all working.
Multiplying numerator and denominator by
Multiplying both sides by
d \:\tan \theta_2-h) = h \:\tan \theta_2" alt="\tan \theta_1\d \:\tan \theta_2-h) = h \:\tan \theta_2" />
Adding to both sides
Factorizing the RHS
\tan \theta_1 + \tan \theta_2)" alt="d\:\tan \theta_1 \: \tan \theta_2 = h\\tan \theta_1 + \tan \theta_2)" />
Dividing both sides by