1+sinx/1-sinx=((1+tan(x/2))/(1+tan(x/2))^2 Need to prove it but cant get my head round it!!if anyone could help asap!!thanks!!
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Originally Posted by cute_poison 1+sinx/1-sinx=((1+tan(x/2))/(1+tan(x/2))^2 Need to prove it but cant get my head round it!!if anyone could help asap!!thanks!! Ok, before I work on this, let me make sure I am working the problem you have because this: is not necessarily true, since is not always true.
Originally Posted by sinewave85 Ok, before I work on this, let me make sure I am working the problem you have because this: is not necessarily true, since is not always true. Your RHS simplifies to 1 so I'd imagine the OP meant
Originally Posted by e^(i*pi) Your RHS simplifies to 1 so I'd imagine the OP meant Yeah, I read it wrong, thanks.
I hope what the op meant was: since that is how I think it reads. (The square is outside the brackets for the right-hand denominator).
In either case, you are going to need the half-angle identities for tan, which are:
Hello cute_poison Originally Posted by cute_poison 1+sinx/1-sinx=((1+tan(x/2))/(1+tan(x/2))^2 Need to prove it but cant get my head round it!!if anyone could help asap!!thanks!! I think you must have made a typo in your original posting, but perhaps this is what you meant: Prove the identity If then . (For instance, see Half Angle Formula) Does that help? Grandad
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