can anybody solve this question? it just a simple question but i forgot because i left math behind for a long time.. simplify cos^2(x)/(1-sinx) thanks in advance
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Is the sin(x) in the denominator supposed to be squared or not? Just wondering. It's not now as I see it.
(1+sin x) just write cos^2x=(1-sin^2 x)
Originally Posted by Jameson Is the sin(x) in the denominator supposed to be squared or not? Just wondering. It's not now as I see it. no.. not to be squared
Originally Posted by sbcd90 (1+sin x) just write cos^2x=(1-sin^2 x) that's it?
Originally Posted by lanzailan can anybody solve this question? it just a simple question but i forgot because i left math behind for a long time.. simplify cos^2(x)/(1-sinx) thanks in advance $\displaystyle \frac{cos^2x}{1-sinx}$ $\displaystyle =\frac{(1-sin^2x)}{1-sinx}$ $\displaystyle =\frac{(1+sinx)(1-sinx)}{1-sinx}$ What is left ?
Originally Posted by mathaddict $\displaystyle \frac{cos^2x}{1-sinx}$ $\displaystyle =\frac{(1-sin^2x)}{1-sinx}$ $\displaystyle =\frac{(1+sinx)(1-sinx)}{1-sinx}$ What is left ? thanks anyway..
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