I'm trying to graph a sine function and I have five points. I transform them using the parameters of the rule I'm given but I don't have enough coordinates in order to draw the curve properly. Does anybody know how I can create more coordinates by using the ones I already have (I have 5) so that I can graph it?
Any help would be greatly appreciated!
Thanks in advance!
Just remembering this myself, so maybe I won't be of much help but I will try!
f(x) = 5 sin (-πx/4) - 3
I believe that 5 at the beginning can be used as the slope (or 5/1). I think this is true because of the form y = mx + b.
y = f(x)
m = 5/1
x = sin(-nx/4)
b = -3
m is a slope.
Using the slope you can take a point and add 5 to the y value, and 1 to the x value. This is because a slope is arranged in rise over run form.
5(rise) / 1 (run)
Well... this could be completely wrong but if you have an answer sheet that you can check your answer on it's a worth a shot to see if it is correct. However, if you don't have an answer sheet, you should probably wait for someone that knows for certain.