$\displaystyle \frac{(\sqrt{5}tan \theta)^2*\sqrt{5}sec^2 \theta}{\sqrt{5 +5tan^2\theta}}$

is supposed to equal $\displaystyle 5tan^2\theta$

it's the part in the middle that's screwing me :o

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- Feb 28th 2009, 02:02 PMTYTYtrig equality - stick
$\displaystyle \frac{(\sqrt{5}tan \theta)^2*\sqrt{5}sec^2 \theta}{\sqrt{5 +5tan^2\theta}}$

is supposed to equal $\displaystyle 5tan^2\theta$

it's the part in the middle that's screwing me :o - Feb 28th 2009, 02:52 PMskeeter
did you post the numerator correctly?

here's what can be done with the denominator ...

$\displaystyle \sqrt{5 + 5\tan^2{\theta}}

$

$\displaystyle \sqrt{5(1 + \tan^2{\theta})}

$

$\displaystyle \sqrt{5\sec^2{\theta}}$