Find an angle x in radians such that 8pi<x<9pi and cosx=1/2
What is this question asking for? I came up with pi/3, but I don't think that's in between 8 and 9 pi. Can anyone explain? Thanks
Remember that is periodic with a a period of which means you get your original answer of and add 4 lots of (this is 4 periods) to give you an answer of