Find an angle x in radians such that 8pi<x<9pi and cosx=1/2

What is this question asking for? I came up with pi/3, but I don't think that's in between 8 and 9 pi. Can anyone explain? Thanks

Printable View

- February 28th 2009, 06:38 AMcaptaintoast87finding and angle x in radians?
Find an angle x in radians such that 8pi<x<9pi and cosx=1/2

What is this question asking for? I came up with pi/3, but I don't think that's in between 8 and 9 pi. Can anyone explain? Thanks - February 28th 2009, 06:59 AMe^(i*pi)