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Math Help - Please help me graph this equation

  1. #1
    Junior Member
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    Talking Please help me graph this equation

    Hi everyone,

    How do I write this equation in the standard form and then graph it. I don't how I could get a standard circle or a hyperbola equation from the following. I am to graph the equation after writing it but I'm sure I can if I can write it in the correct standrd form. Here it is.

    9x^2 - y^2 = -16

    Please help me.

    Thanks
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  2. #2
    Senior Member OReilly's Avatar
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    Quote Originally Posted by coopsterdude View Post
    Hi everyone,

    How do I write this equation in the standard form and then graph it. I don't how I could get a standard circle or a hyperbola equation from the following. I am to graph the equation after writing it but I'm sure I can if I can write it in the correct standrd form. Here it is.

    9x^2 - y^2 = -16

    Please help me.

    Thanks
    You can solve equation for y:
    \begin{array}{l}<br />
 9x^2  - y^2  =  - 16 \\ <br />
 y^2  = 9x^2  + 16 \\ <br />
 y = \sqrt {9x^2  + 16}  \\ <br />
 \end{array}<br />

    Then you can graph function: f(x) = \sqrt {9x^2  + 16}


    Here is graph:
    Attached Thumbnails Attached Thumbnails Please help me graph this equation-image1.gif  
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  3. #3
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by OReilly View Post
    You can solve equation for y:
    \begin{array}{l}<br />
 9x^2  - y^2  =  - 16 \\ <br />
 y^2  = 9x^2  + 16 \\ <br />
 y = \sqrt {9x^2  + 16}  \\ <br />
 \end{array}<br />

    Then you can graph function: f(x) = \sqrt {9x^2  + 16}


    Here is graph:
    Note though that when you take the square root you have to provide BOTH possibilities: + and -:
    y = \pm \sqrt{9x^2+16}

    -Dan
    Attached Thumbnails Attached Thumbnails Please help me graph this equation-hyperbola.jpg  
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  4. #4
    Senior Member OReilly's Avatar
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    Quote Originally Posted by topsquark View Post
    Note though that when you take the square root you have to provide BOTH possibilities: + and -:
    y = \pm \sqrt{9x^2+16}

    -Dan
    Yes, minus for me...
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