The problem is in the attachment. (a matrix involve trigonometry). I wonder if anybody can help!

yybn(Crying)

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- Feb 23rd 2009, 01:48 PMyybnCan anyone help with a linear alg problem
The problem is in the attachment. (a matrix involve trigonometry). I wonder if anybody can help!

yybn(Crying) - Feb 23rd 2009, 03:11 PMPlato
Look at the case where $\displaystyle \theta _1 = 0\;\& \,\theta _2 = \frac{\pi }{2}$

- Feb 23rd 2009, 03:58 PMyybnThanks Plato
Thanks! Plato(Hi)

This sounds a very good idea to start. But could you give me a more general proof? ( the formula to be used are:

sin(X+Y)= sin (X)cos(Y)+cos(X)sin (Y)

cos(X+Y)=cos(X)cos(Y)-sin(X)sin(Y)

Thanks a lot!

yybn