The sine function is 1 at 90 degrees or
Therefore,
I find it hard to type the problem on the computer, so I included a picture with a note on where I am stuck. I know I can't divide "1" by "sin2theta" to get 30 degrees, so I don't know what to do next. Thanks.
As you have written, Where, in the interval , is equal to 1? That would be But in our case, the angle is So
and
If you substitute these back into the original equation, you'll see that the solution is and the second angle of is an extraneous solution introduced when you squared both sides.