I am rotating a 2 perpendicular fixed lines 6.5°.

How would I calculate Y1 (vertical change of the end points) and X1 (horizontal change of end points)?

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- Feb 20th 2009, 09:32 AMProgStuck on trig
I am rotating a 2 perpendicular fixed lines 6.5°.

How would I calculate Y1 (vertical change of the end points) and X1 (horizontal change of end points)? - Feb 20th 2009, 10:35 AMrunning-gag
Hi

Using complex numbers (there are other methods) I can find :

$\displaystyle X_1 = 2500 \cos(6.5°) - 3000 \sin(6.5°) -2500 = -355.68$

$\displaystyle Y_1 = 2500 \sin(6.5°) + 3000 \cos(6.5°) - 3000 = 263.72$