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    why is math hard

    convert the rectangular to polar (-2,3)
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  2. #2
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    Quote Originally Posted by SHORTY View Post
    convert the rectangular to polar (-2,3)
    We know that
    x = r \, cos \theta
    y = r \, sin \theta

    So, upon inverting this:
    r = \sqrt{x^2 + y^2}
    \theta = atn \left ( \frac{y}{\sqrt{x^2+y^2}} \right )

    (Which you can likely look up. I can never seem to remember the equations, so I derive them.)

    Anyways:
    r = \sqrt{(-2)^2 + 3^2} = \sqrt{4+9} = \sqrt{13}
    \theta = atn \left ( \frac{3}{\sqrt{(-2)^2+3^2}} \right ) = atn \left ( \frac{3}{\sqrt{13}} \right ) (radians)

    Off the top of my head I don't believe that the angle simplifies.

    -Dan
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