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Math Help - Solving Trigonometric Equations

  1. #1
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    Solving Trigonometric Equations

    How do you solve:

    3\cot^2 {x} + 4\csc^2 {x} = -4

    and

    2\sin {x} \cos {x} +4\sin {x} = \cos {x} +2

    within 0 \leq x \leq 2\pi ?
    Last edited by chrozer; February 14th 2009 at 12:15 PM.
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  2. #2
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    Quote Originally Posted by chrozer View Post
    How do you solve:

    3\cot^2 {x} + 4\csc^2 {x} = -4

    note: use the identity \textcolor{red}{\csc^2{x} = 1 + \cot^2{x}}

    and

    2\sin {x} \cos {x} +4\sin {x} = \cos {x} +2

    factor ... \textcolor{red}{2\sin{x}(\cos{x} + 2) = \cos{x} + 2}

    so ... \textcolor{red}{2\sin{x}} must equal what?

    within 0 \leq x \leq 2\pi ?
    hope it helps.
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  3. #3
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    Thnx I got it now.
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