2cos²θ+6cosθ=3

**sarabara** · February 11th 2009, 01:46 AM

thanks for your help!

**mathaddict** · February 11th 2009, 02:05 AM

This is the same as one of your previos thread .

First , replace $\cos\theta$ with x . After that use the quadratic formula to find x , then solve for $\theta$

Thread: 2cos²θ+6cosθ=3

LinkBack

Thread Tools

Display

2cos²θ+6cosθ=3

Similar Math Help Forum Discussions

(2cos(x/2)sin(x/2))/2cos^2(x/2)

show that x^4 - 3x^2 + 1 = 0 when x is given as 2cos(π/5)

? Each time you see (cos(2x))^2, replace it with 1/2 + 1/2cos(4x) ?

need help integrating x^2cos(x^2)dx

8sin^2(v)-2cos(v)=5

Search Tags