# Math Help - tan²θ=-tanθ+3

1. ## tan²θ=-tanθ+3

thank you for any help!

2. Do you know how to solve $y^2 = -y + 3$ ?

3. $\tan^2\theta+\tan\theta-3=0$

Let $\tan\theta=x$ , thus $x^2+x-3=0$'

$x=\frac{-1+\sqrt{13}}{2}$
or $x=\frac{-1-\sqrt{13}}{2}$
Replace x with $\tan\theta$ , then solve for $\theta$