1. Given: f(x)=arcsin(x/3)+5, and -3<=x<=3
I got y= sin^-1(x-5)*5
Last edited by qbkr21; Nov 6th 2006 at 01:19 PM.
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I'm confused on your notation. What does f(x)^1 mean? Is that supposed to be the inverse, or ?
yes I am sorry
Mmk. So to do this problem, just switch x and y.
Switch x's and y's.
Take the sine of both sides. Can you finish it?
Last edited by Jameson; Nov 6th 2006 at 01:55 PM.
No I got to thant point, I can finish it.
What happens when you take a sin^-1 back across the equal's sign. Does it change back to just plain sin ?
Take the sine of both sides.
Thanks Jameson, you are the Master of Math!!! And God's Gift to us all!!!
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